If 31z5 is a multiple of 3, where z is a digit, what are all possible values of z?

Type: MCQ • Marks: 1

A. 1, 4, 7

B. 2, 5, 8

C. 0, 1, 2

D. 0, 3, 6, 9

Explanation

Sum = 3+1+z+5 = 9+z. For 9+z to be a multiple of 3, z can be 0, 3, 6, 9. Wait, 9+0=9, 9+3=12, 9+6=15, 9+9=18. So z = 0, 3, 6, 9.

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Class 7th Ganita Prakash 1

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