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Algebraic Expressions and Identities - बीजीय व्यंजक एवं सर्वसमिकाएँ

विस्तारित कीजिए:- (x+5)(x+3)(x + 5)(x + 3)(x+5)(x+3)

Type: DESCRIPTIVE • Marks: 2
विस्तारित कीजिए:- (x+5)(x+3)(x + 5)(x + 3)(x+5)(x+3)
Answer
x(x+3)+5(x+3)x(x + 3) + 5(x + 3)x(x+3)+5(x+3) =x2+3x+5x+15= x^2 + 3x + 5x + 15=x2+3x+5x+15 =x2+8x+15= x^2 + 8x + 15=x2+8x+15
Explanation
x(x+3)+5(x+3)x(x + 3) + 5(x + 3)x(x+3)+5(x+3) =x2+3x+5x+15= x^2 + 3x + 5x + 15=x2+3x+5x+15 =x2+8x+15= x^2 + 8x + 15=x2+8x+15
Class 8th Math (Short & Long)

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