• Mayur Vihar 3 Delhi, 110096 India

Back to Test Series
Algebraic Expressions and Identities - बीजीय व्यंजक एवं सर्वसमिकाएँ

सर्वसमिका का उपयोग करके सिद्ध कीजिए:- (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2(a+b)2=a2+2ab+b2

Type: DESCRIPTIVE • Marks: 2
सर्वसमिका का उपयोग करके सिद्ध कीजिए:- (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2(a+b)2=a2+2ab+b2
Answer
(a+b)(a+b)(a + b)(a + b)(a+b)(a+b) =a(a+b)+b(a+b)= a(a + b) + b(a + b)=a(a+b)+b(a+b) =a2+ab+ab+b2= a^2 + ab + ab + b^2=a2+ab+ab+b2 =a2+2ab+b2= a^2 + 2ab + b^2=a2+2ab+b2
Explanation
(a+b)(a+b)(a + b)(a + b)(a+b)(a+b) =a(a+b)+b(a+b)= a(a + b) + b(a + b)=a(a+b)+b(a+b) =a2+ab+ab+b2= a^2 + ab + ab + b^2=a2+ab+ab+b2 =a2+2ab+b2= a^2 + 2ab + b^2=a2+2ab+b2
Class 8th Math (Short & Long)

Practice more

This page is indexed for search so students can find questions directly from Google.

View full Test Series Browse Test Series
Login / Register
Go Back Top