If 3 men or 6 boys can do a piece of work in 20 days, in how many days can 6 men and 8 boys do the same work?

Type: MCQ • Marks: 1

A. 1) 8 days

B. 2) 10 days

C. 3) 6 days

D. 4) 5 days

Explanation

3M = 6B => 1M = 2B. Total work = 6B * 20 = 120 B-days. 6M + 8B = 12B + 8B = 20B. Days required = 120 / 20 = 6 days.

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UP TGT Mathematics

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