If a variable takes values 1, 2, 3, ... n with frequencies proportional to 1, 2, 3, ... n respectively, find its mean.

Type: MCQ • Marks: 1

A. (3n + 1) / 4

B. (n + 1) / 2

C. (2n + 1) / 3

D. (n + 2) / 3

Explanation

sum(f * x) = sum(x^2) = n(n+1)(2n+1)/6. sum(f) = sum(x) = n(n+1)/2. Mean = [n(n+1)(2n+1)/6] / [n(n+1)/2] = (2n + 1) / 3.

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