The standard deviation of first 'n' natural numbers is given by the formula:

Type: MCQ • Marks: 1

A. 1) (n^2 - 1) / 12

B. 2) sqrt((n^2 + 1) / 12)

C. 3) sqrt((n - 1) / 6)

D. 4) sqrt((n^2 - 1) / 12)

Explanation

Standard Deviation of first n natural numbers = sqrt((n^2 - 1) / 12).

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UP TGT Mathematics

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