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UP TGT Mathematics Set Theory Test Series - Part 5

For f:ℝ→ℝ, f(x)=x², the function is onto

Type: MCQ • Marks: 1
For f:ℝ→ℝ, f(x)=x², the function is onto
Options
A. no, because negative reals are not attained
B. no, because f(0)=0
C. yes, every real has a square root in ℝ
D. yes, because it is even
Explanation
No real x satisfies x²=−1, so negative codomain values have no preimage.
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