The product of the perpendicular distances from (x₁, y₁) to the pair of lines ax² + 2hxy + by² = 0 is:

Type: MCQ • Marks: 1

A. (ax₁² + 2hx₁y₁ + by₁²) / √((a - b)² + 4h²)

B. (ax₁² + 2hx₁y₁ + by₁²) / (a + b)

C. √(ax₁² + by₁²)

D. (2hx₁y₁) / (a + b)

Explanation

Standard distance product formula for homogeneous pair of lines.

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