Position vector of a particle in circular motion is r = R(cos ωt i^ + sin ωt j^). Its velocity vector v is:

Type: MCQ • Marks: 1

A. R (sin ωt i^ - cos ωt j^)

B. R ω (-sin ωt i^ + cos ωt j^)

C. R ω (cos ωt i^ + sin ωt j^)

D. -R ω^2 (cos ωt i^ + sin ωt j^)

Explanation

v = dr/dt = R d/dt(cos ωt) i^ + R d/dt(sin ωt) j^ = -R ω sin ωt i^ + R ω cos ωt j^ = R ω (-sin ωt i^ + cos ωt j^).

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UP TGT Mathematics

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