A projectile is launched at 50 m/s at 45° above horizontal. Taking g=10 m/s², find its maximum height.

Type: MCQ • Marks: 1

A. 31.25 m

B. 64.5 m

C. 62.5 m

D. 125 m

Explanation

H = u² sin²θ/(2g) = (50)² sin²45°/(2·10) = 62.5 m.

Want to attempt the full test series with a timer and instant score? Purchase the package to unlock the complete test. Purchase Now

UP TGT Mathematics

This page is indexed for search so students can find questions directly from Google.

Welcome to TutorWale!