Two angles of projection for a given velocity u to attain the same horizontal range R are:

Type: MCQ • Marks: 1

A. θ and 90° + θ

B. θ and 180° - θ

C. θ and (90° - θ)

D. θ and θ/2

Explanation

Since sin 2θ = sin(180° - 2θ) = sin(2(90° - θ)), complementary angles θ and 90° - θ yield the exact same horizontal range.

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UP TGT Mathematics

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