For the inclined plane projectile in Q89, the maximum range along the inclined plane is:

Type: MCQ • Marks: 1

A. u² / (2g sin α)

B. u² / (g (1 + sin α))

C. u² / (g cos²α)

D. 2u² / g

Explanation

Maximum range up/down an inclined plane of angle α is given by R_max = u² / [g(1 ± sin α)].

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UP TGT Mathematics

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